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P(Z>1.96)? given Z has the sn dist(Z~N(0, 1)). HELP!!!!

taglines

That’s probably the coolest tagline I’ve seen in a while (although Dennis isn’t doing too bad, with “Corporate America: Where Fun Goes to Die.”)

But, soliciting other Jambo users for hard-core statistics, not bad at all. If anyone can help her, fire up your Jambo client and get in there. Thanks people.

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This entry was posted on Thursday, January 25th, 2007 at 4:54 pm and is filed under Mobile Social Software. You can follow any responses to this entry through the RSS 2.0 feed. Both comments and pings are currently closed.

One Response to “P(Z>1.96)? given Z has the sn dist(Z~N(0, 1)). HELP!!!!”

  1. valier Says:
    January 26th, 2007 at 1:18 am

    P ( 0 < Z < 1 ) = .34

    P ( -1 < Z < 1 ) = .68

    P ( -2 < Z < 2 ) = .954

    P ( -1.96 < Z < 1.96 ) = .95

    P ( -3 < Z < 3 ) = .9974

    so...

    P ( Z > 1.96 ) = 1-.95 = .05/2 = .025
    z is everything greater than 1.96, or 2 stdev away from the mean (0)… so take the total (which is always 1) minus 95% and then divide that in half since we’re only talking about half of the “graph.”

    and then…
    P ( Z > -1.96 ) = .95 + .025 = .975

    P ( 0 < Z < 1.96 ) = .95/2 = .475

    P ( -1 < Z < 1.96 ) = .95/2 + .68/2 = .475 + .34 = .815

    enjoy!